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x^2+15x=2700
We move all terms to the left:
x^2+15x-(2700)=0
a = 1; b = 15; c = -2700;
Δ = b2-4ac
Δ = 152-4·1·(-2700)
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11025}=105$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-105}{2*1}=\frac{-120}{2} =-60 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+105}{2*1}=\frac{90}{2} =45 $
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